Show that C_0+C_1+C_2+ +C_9=512 - Vidyadip

Question

Show that $C_0+C_1+C_2+\ldots \ldots+C_9=512$

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Answer

Since $C_0+C_1+C_2+C_3+\ldots . .+C_n=2^n$
Putting n = 9, we get
$C_0+C_1+C_2+\ldots . .+C_9=2^9$
$\therefore C_0+C_1+C_2+\ldots . .+C_9=512$

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