Question
Show that the function given by f(x) = 3x + 17 is increasing on R.

Answer

Let $x_1$ and $x_2$ be any two numbers in R such that
$x_1$ < $x_2$
$\Rightarrow$ $3x_1 < 3x_2$
$\Rightarrow$ $3x_1 + 17 < 3x_2 + 17$
$\Rightarrow$ $f(x_1) < f(x_2)$
Therefore, f is strictly increasing on R.

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