Question
Show that the function given by f(x) = 3x + 17 is strictly increasing on R.

Answer

Given: f(x) = 3x + 17
$\therefore$ f'(x) = 3(1) + 0 = 3 >0 i.e., positive for all $\text{x}\in \text{R}$
Therefore, f(x) is strictly increasing on R.

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