Question
Show that the path of a moving point such that its distances from two lines 3x - 2y = 5 and 3x + 2y = 5 are equal is a straight line.

Answer

Let P(h, k) be a moving point such that it is equidistant from the lines 3x - 2y - 5 = 0 and 3x + 2y - 5 = 0, then $\Big|\frac{3\text{h}-2\text{k}-5}{\sqrt{9+4}}\Big|=\Big|\frac{3\text{h}+2\text{k}-5}{\sqrt{9+4}}\Big|$ $|3\text{h}-2\text{k}-5|=|3\text{h}+2\text{k}-5|$ $4\text{k}=0\Rightarrow\text{k}=0$ or $6\text{h}-10=0\Rightarrow3\text{h}=5$ Hence, the locus of (h, k) is y = 0 or 3x = 5, which are straight lines.

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