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Quadratic Equations — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsQuadratic Equations2 Marks
Question
Show the following quadratic equation by factorization method:
$27x^2 - 10x + 1 = 0$
✓

Answer

$27x^2 - 10x + 1 = 0$
We will apply discriminant rule,
$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$
Where $D = b^2 - 4ac$
$= (-10)^2 - 4.27.1$
$= 100 - 108$
$= -4$
From (A)
$\text{x}=\frac{-(-10)\pm\sqrt{-8}}{54}$
$=\frac{10\pm2\sqrt{2}\text{i}}{54}$
$\frac{5\pm\sqrt{2}\text{i}}{27}$
$\therefore\text{x}=\frac{5}{27}+\frac{\sqrt{2\text{i}}}{27},\frac{5}{27}-\frac{\sqrt{2}}{27}\text{i}$

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