Question
Show the following quadratic equation by factorization method: $2x^2 + x + 1 = 0$

Answer

$2x^2 + x + 1 = 0$ We will apply discriminant rule, $\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$ Where $D = b^2 - 4ac = 1^2 - 4.2.1 = 1 - 8 = -7$ From (A) $\text{x}=\frac{-1\pm\sqrt{-7}}{2.2}$
$=\frac{-1\pm\sqrt{7}\text{ i}}{4}$ $\therefore\text{x}=\frac{-1}{4}\pm\frac{\sqrt{7}}{4}\ \text{i}$

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