Question
Show the following quadratic equation by factorization method:
$\text{x}^2 +2\text{ x} +\frac{3}{2}=0$

Answer

$\text{x}^2 +2\text{ x} +\frac{3}{2}=0$

We will apply discriminant rule,

$\text{x}=\frac{-\text{b}\pm\sqrt{\text{D}}}{2\text{a}}\ ...(\text{A})$

Where D = b2 - 4ac

$=(-2)^2-4(1)\Big(\frac{3}{2}\Big)$

= 4 - 6

= -2

From (A)

$\text{x}=\frac{-(-2)\pm\sqrt{-2}}{2(1)}$

$=\frac{2\pm\text{i}\sqrt{2}}{2}$

$=1\pm\frac{\text{i}}{\sqrt{2}}$

Thus,

$\therefore\text{x}=1\pm\frac{\text{i}}{\sqrt{2}}$

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