Question
Show thet the followiong sequences is an A.P. Also, find the common difference and write 3 more terms in each case.
$9,\ 7,\ 5,\ 3,\ ...$

Answer

$9,7,5,3,...$
$​​\text{a}_4-​​\text{a}_3=​​\text{a}_3-​​\text{a}_2-​​\text{a}_1=-2$
$\therefore$ The comman difference is -2
and the given sequence is A.P
$​​\text{a}_5=9+(-2)(5-1)=1$
$​​\text{a}_6=9+(-2)(6-1)=-1$
$​​\text{a}_7=9+(-2)(7-1)=-3$

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