We have,
$|A|=1(-3-0)-0+0=-3$
Now,
$A_{11}=-3-0=-3, A_{12}=-(-3-0)=3, A_{13}=6-15=-9$
$A_{22}=-(0-0)=0, A_{22}=-1-0=-1, A_{22}=-(2-0)=-2$
$A_{31}=0-0=0, A_{32}=-(0-0)=0, A_{33}=3-0=3$
$\therefore a d j A=\left[\begin{array}{ccc}-3 & 0 & 0 \\ 3 & -1 & 0 \\ -9 & -2 & 3\end{array}\right]$
$\therefore A^{-1}=\frac{1}{|A|}$ $adjA = - \frac{1}{3}\left[\begin{array}{ccc}-3 & 0 & 0 \\ 3 & -1 & 0 \\ -9 & -2 & 3\end{array}\right]$
ધારો કે $a \in S$ અને $A =\left[\begin{array}{ccc}1 & 0 & a \\ -1 & 1 & 0 \\ - a & 0 & 1\end{array}\right]$ છે.
જો $\sum_{ a \in S } \operatorname{det}(\operatorname{adj} A )=100 \lambda$ હોય, તો $\lambda$ .........
$2 x+y-z=5$
$2 x-5 y+\lambda z=\mu$
$x+2 y-5 z=7$
ને અસંખ્ય ઉકેલો હોય,તો
$(\lambda+\mu)^2+(\lambda-\mu)^2=........$