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Structure of Atom — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryStructure of Atom3 Marks
Question
Similar to electron diffraction, neutron diffraction microscope is also used for the determination of the structure of molecules. If the wavelength used here is 800pm, calculate the characteristic velocity associated with the neutron.
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Answer

From de Broglie’s equation,
$\lambda=\frac{\text{h}}{\text{mv}}$
$\text{v}=\frac{\text{h}}{\text{m}\lambda}$
Where,
v = velocity of particle (neutron)
h = Planck’s constant
m = mass of particle (neutron)
$\lambda$ = wavelength
Substituting the values in the expression of velocity (v),
$\text{v}=\frac{6.626\times10^{-34}\text{Js}}{(1.67493\times10^{-27}\text{kg})(800\times10^{-12}\text{m})}$
$=4.94\times10^2\text{ms}^{-1}$
$\text{v}=494\text{ms}^{-1}$
$\therefore$ Velocity associated with the neutron = $494 \mathrm{ms}^{-1}$

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