Question
Simplify:
$(2^{-1}+3^{-1})^{-1}$

Answer

$(2^{-1}+3^{-1})^{-1}=\Big(\frac{1}{2}+\frac{1}{3}\Big)^{-1}=\Big(\frac{3+2}{6}\Big)^{-1}$
$=\Big(\frac{5}{6}\Big)^{-1}=\frac{6}{5}$

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