Question
Solve:
$16 a ^2- b ^4$
$16 a ^2- b ^4$
✓
Answer
$16 a^2-b^4$
$=\left(4 a^2\right)^2-\left(b^2\right)^2$
$=\left(4 a^2+b^2\right)\left(4 a^2-b^2\right)$
$=\left(4 a^2+b^2\right)\left[(2 a)^2-b^2\right]$
$=\left(4 a^2+b^2\right)(2 a+b)(2 a-b)$
$=\left(4 a^2\right)^2-\left(b^2\right)^2$
$=\left(4 a^2+b^2\right)\left(4 a^2-b^2\right)$
$=\left(4 a^2+b^2\right)\left[(2 a)^2-b^2\right]$
$=\left(4 a^2+b^2\right)(2 a+b)(2 a-b)$
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