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Algebra — MATHS STD 10 — Question

Tamilnadu BoardEnglish MediumSTD 10MATHSAlgebra5 Marks
Question
Simplify $\frac{(2 x+1)(x-2)}{x-4}-\frac{\left(2 x^2-5 x+2\right)}{x-4}$
✓

Answer

$\begin{aligned} & \frac{(2 x+1)(x-2)}{x-4}-\frac{\left(2 x^2-5 x+2\right)}{x-4} \\ & =\frac{(2 x+1)(x-2)-\left(2 x^2-5 x+2\right)}{x-4} \\ & =\frac{2 x^2-4 x+x-2-2 x^2+5 x-2}{x-4} \\ & =\frac{2 x-4}{x-4} \\ & =\frac{2(x-2)}{x-4}\end{aligned}$

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