Question
Simplify:
$2 x^2\left(x^3-x\right)-3 x\left(x^4+2 x\right)-2\left(x^4-3 x^2\right)$
$2 x^2\left(x^3-x\right)-3 x\left(x^4+2 x\right)-2\left(x^4-3 x^2\right)$
✓
Answer
To simplify, we will use distributive law as follows:
$2 x^2\left(x^3-x\right)-3 x\left(x^4+2 x\right)-2\left(x^4-3 x^2\right)$
$=2 x^5-2 x^3-3 x^5-6 x^2-2 x^4+6 x^2$
$=2 x^5-3 x^5-2 x^4-2 x^3-6 x^2+6 x^2$
$=-x^5-2 x^4-2 x^3$
$2 x^2\left(x^3-x\right)-3 x\left(x^4+2 x\right)-2\left(x^4-3 x^2\right)$
$=2 x^5-2 x^3-3 x^5-6 x^2-2 x^4+6 x^2$
$=2 x^5-3 x^5-2 x^4-2 x^3-6 x^2+6 x^2$
$=-x^5-2 x^4-2 x^3$
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