Given, $\frac{3}{7}\div\Big(\frac{21}{-55}\Big)$ The reciprocal of $\Big(\frac{21}{-55}\Big)$ is $\frac{-55}{21}$ So, $\frac{3}{7}\div\Big(\frac{21}{-55}\Big)$ $=\frac{3}{7}\times\frac{(-55)}{21}$ $\frac{(-55)\times3}{7\times21}=\frac{-55}{49}$
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