Question
Simplify:
$ (3 x+2 y)^2-(3 x-2 y)^2 $

Answer

$ (3 x+2 y)^2-(3 x-2 y)^2 $
$ =[(3 x+2 y)+(3 x-2 y)][(3 x+2 y)-(3 x-2 y)] $
$ =(3 x+2 y+3 x-2 y)(3 x+2 y-3 x+2 y) $
$ =6 x \times 4 y $
$ =(6 \times 4) \times x y $
$ =24 x y $

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