$\begin{aligned} & \frac{5 t ^3}{4 t -8} \times \frac{6 t -12}{10 t }=\frac{5 t ^3 \times 6( t -2)}{4( t -2) \times 10 t } \\ & =\frac{5 t ^3 \times 6}{4 \times 10 t } \\ & =\frac{3}{4} t ^2\end{aligned}$
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