Question
Simplify: $5\frac{1}{7}-\Big\{3\frac{3}{10}\div\Big(2\frac{4}{5}-\frac{7}{10}\Big)\Big\}$
✓
Answer
Given expression: $5\frac{1}{7}-\Big\{3\frac{3}{10}\div\Big(2\frac{4}{5}-\frac{7}{10}\Big)\Big\}$
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\Big(\frac{14}{5}-\frac{7}{10}\Big)\Big\}$
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\Big(\frac{28-7}{10}\Big)\Big\}$
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\frac{21}{10}\Big\}$ (Removing parentheses)
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\frac{10}{21}\Big\}$ (Removing $'÷')$
$=\frac{36}{7}-\frac{11}{7}$ (Removing braces)
$=\frac{36-11}{7}=\frac{25}{7}=3\frac{4}{7}$ (Simplifying)
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\Big(\frac{14}{5}-\frac{7}{10}\Big)\Big\}$
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\Big(\frac{28-7}{10}\Big)\Big\}$
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\frac{21}{10}\Big\}$ (Removing parentheses)
$=\frac{36}{7}-\Big\{\frac{33}{10}\div\frac{10}{21}\Big\}$ (Removing $'÷')$
$=\frac{36}{7}-\frac{11}{7}$ (Removing braces)
$=\frac{36-11}{7}=\frac{25}{7}=3\frac{4}{7}$ (Simplifying)
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