Question
Simplify: $\frac{8^{\frac{1}{2}}}{8^{\frac{2}{3}}}$

Answer

$\frac{8^{\frac{1}{2}}}{8^{\frac{2}{3}}}=8^{\big(\frac{1}{2}-\frac{2}{3}\big)}$ $=8^{\big(\frac{3-4}{6}\big)}=8^{\frac{-1}{6}}$

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