Question
Simplify: $\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$

Answer

$\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$
$LCM$ of $11, 3, 4 = 11 \times 3 \times 4 = 132$
$\therefore\frac{-9}{11}=\frac{-9\times12}{11\times12}=\frac{-108}{132}$
$\frac{2}{3}=\frac{2\times44}{3\times44}=\frac{88}{132}$
$\frac{-3}{4}=\frac{-3\times33}{4\times33}=\frac{-99}{132}$
$\therefore\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$
$=\frac{-108}{132}+\frac{88}{132}+\frac{-99}{132}$
$=\frac{-108+88+(-99)}{132}$
$=\frac{-108+88-99}{132}$
$=\frac{-207+88}{132}$$=\frac{-119}{132}$

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