Question
Simplify:
$(a^2+ b^2+ 2ab) - (a^2+ b^2- 2ab)$
$(a^2+ b^2+ 2ab) - (a^2+ b^2- 2ab)$
✓
Answer
We have:
$(a^2+ b^2+ 2ab) - (a^2+ b^2- 2ab)$
$= a^2+ b^2+ 2ab - a^2- b^2+ 2ab $
$= a^2- a^2+ b^2- b^2+ 2ab + 2ab $
$= 0 + 0 + (2 + 2)ab $
$= 4ab$
$(a^2+ b^2+ 2ab) - (a^2+ b^2- 2ab)$
$= a^2+ b^2+ 2ab - a^2- b^2+ 2ab $
$= a^2- a^2+ b^2- b^2+ 2ab + 2ab $
$= 0 + 0 + (2 + 2)ab $
$= 4ab$
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