Question
Simplify and write the following in exponential form:
$\frac{3^2\times7^8\times13^6}{(21)^2\times(91)^3}$
$\frac{3^2\times7^8\times13^6}{(21)^2\times(91)^3}$
✓
Answer
$\frac{3^2\times7^8\times13^6}{(21)^2\times(91)^3}$
$=\frac{3^2\times7^27^6\times(13)^6}{(21)^2\times(13)^3\times(7)^3}$
$=\frac{(21)^2\times7^6\times(13)^6}{(21)^2\times(13)^3\times(7)^3}$
$=\frac{7^6\times(13)^6}{(13)^3\times(7)^3}$
$=\frac{91^6}{91^3}$
$=(91)^{6-3}$
$=(91)^3$
$=\frac{3^2\times7^27^6\times(13)^6}{(21)^2\times(13)^3\times(7)^3}$
$=\frac{(21)^2\times7^6\times(13)^6}{(21)^2\times(13)^3\times(7)^3}$
$=\frac{7^6\times(13)^6}{(13)^3\times(7)^3}$
$=\frac{91^6}{91^3}$
$=(91)^{6-3}$
$=(91)^3$
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