Question
Simplify:$\Big(\frac{32}{243}\Big)^{-\frac{4}{5}}$
✓
Answer
$\Big(\frac{32}{243}\Big)^{-\frac{4}{5}}$$=\Big(\frac{243}{32}\Big)^{\frac{4}{5}}$
$=\Big(\frac{3^5}{2^5}\Big)^{\frac{4}{5}}$
$=\frac{3^{5\times\frac{4}{5}}}{2^{5\times\frac{4}{5}}}$
$=\frac{3^4}{2^4}$
$=\frac{81}{16}$
$=\Big(\frac{3^5}{2^5}\Big)^{\frac{4}{5}}$
$=\frac{3^{5\times\frac{4}{5}}}{2^{5\times\frac{4}{5}}}$
$=\frac{3^4}{2^4}$
$=\frac{81}{16}$
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