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Powers — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSPowers2 Marks
Question
Simplify: $\bigg[\Big(\frac{1}{3}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\bigg]\div\Big(\frac{1}{4}\Big)^{-3}$
✓

Answer

$\bigg[\Big(\frac{1}{3}\Big)^{-3}-\Big(\frac{1}{2}\Big)^{-3}\bigg]\div\Big(\frac{1}{4}\Big)^{-3}$
$=(3^{3}-2^3)\div(4)^3$
$=(27-8)\div64=\frac{19}{64}$

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