Question
Simplify $\frac{11}{18} \times \frac{12}{33} \times \frac{(-6)}{25}$

Answer

Given,$\frac{11}{18} \times \frac{12}{33} \times \frac{(-6)}{25}$
$\therefore$ Product of rational numbers $=\frac{\text { Product of numerators }}{\text { Product of denominators }}$
$\frac{11 \times 12 \times(-6)}{18 \times 33 \times 25}=\frac{11 \times(-72)}{18 \times 825}=\frac{-792}{14850}=\frac{-4}{75}$

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