Question
Simplify:$\frac{16\text{m}^3\text{y}^2}{4\text{m}^2\text{y}}$

Answer

$\frac{16\text{m}^3\text{y}^2}{4\text{m}^2\text{y}}$
$=\frac{16\times\text{m}\times\text{m}\times\text{m}\times\text{y}\times\text{y}}{4\times\text{m}\times\text{m}\times\text{y}}$
$=4\text{m}^{(3-2)}\text{y}^{(2-1)}$
$=4\text{my}$

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