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Fundamental Concepts (Including Fundamental Operations) — MATHS STD 7 — Question

ICSE BoardEnglish MediumSTD 7MATHSFundamental Concepts (Including Fundamental Operations)3 Marks
Question
Simplify: $\left(2 p+\frac{p}{7}\right) \div\left(\frac{9 p}{10}+4 p\right)$
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Answer


$\begin{aligned} & \left(2 \mathrm{p}+\frac{\mathrm{p}}{7}\right) \div\left(\frac{9 \mathrm{p}}{10}+4 \mathrm{p}\right) \\ & =\frac{14 \mathrm{p}+\mathrm{p}}{7} \div \frac{9 \mathrm{p}+40 \mathrm{p}}{10} \\ & =\frac{15}{7} \mathrm{p} \div \frac{49}{10} \mathrm{p} \\ & =\frac{15}{7} \mathrm{p} \times \frac{10}{49 \mathrm{p}} \\ & =\frac{150}{343}\end{aligned}$

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