Question
If $\mathrm{x}$ is $30 \%$ more than $\mathrm{y}$; find: $\frac{\mathrm{y}}{\mathrm{y}-\mathrm{x}}$

Answer

Let $y=a$
Then $\mathrm{x}=\mathrm{a} \times \frac{100+30}{100}$
$ =\mathrm{a} \times \frac{130}{100}=\frac{13}{10} \mathrm{a} $
Now, $\frac{y}{y-x}$
$ =\frac{a}{a-\frac{13}{10} a}=\frac{a}{-\frac{3}{10} a} $
$ =\frac{\mathrm{a} \times 10}{-3 \mathrm{a}}=-\frac{10}{3} $

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