Question
Simplify: $\left(\frac{y}{6}+\frac{2 y}{3}\right) \div\left(y+\frac{2 y-1}{3}\right)$
✓
Answer
$\begin{aligned} & \left(\frac{y}{6}+\frac{2 y}{3}\right) \div\left(y+\frac{2 y-1}{3}\right) \\ & =\left(\frac{y+4 y}{6}\right) \div\left(\frac{3 y+2 y-1}{3}\right) \\ & =\frac{5 y}{6} \div \frac{5 y-1}{3} \\ & =\frac{5 y}{6} \times \frac{3}{5 y-1} \\ & =\frac{5 y}{2(5 y-1)}=\frac{5 y}{10 y-2}\end{aligned}$
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