Question
Simplify $\frac{p^2-10 p+21}{p-7} \times \frac{p^2+p-12}{(p-3)^2}$
✓
Answer
$\begin{aligned} & P ^2-10 p+21=(p-7)(p-3) \\ & p^2+p-12=(p+4)(p-3) \\ & \frac{p^2-10 p+21}{(p-7)} \times \frac{p^2+p-12}{(p-3)^2}=\frac{(p-7)(p-3)}{(p-7)} \times \frac{(p+4)(p-3)}{(p-3)^2} \\ & =(p-3) \times \frac{(p+4)}{(p-3)} \\ & =p+4\end{aligned}$
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