Question
Simplify:
$\left(s^2 \mathrm{t}+\mathrm{tq}^2\right)^2-(2 \mathrm{stq})^2$

Answer

$\left(s^2 \mathrm{t}+\mathrm{tq}^2\right)^2-(2 \mathrm{stq})^2$
$ =\left(s^2 t\right)^2+\left(t q^2\right)^2+2 \times s^2 t \times t q^2-4 s^2 t^2 q^2 $
$=s^4 t^2+t^2 q^4+2 s^2 t^2 q^2-4 s^2 t^2 q^2 $
$ =s^4 t^2+t^2 q^4-2 s^2 t^2 q^2 $​​​​​​​

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