Question
Simplify the expression: ($\sqrt{3} + \sqrt{7})^2$
✓
Answer
The given expression is:
($\sqrt{3} + \sqrt{7})^2$
= ($\sqrt{3})^2 + 2 \times \sqrt{3} \times \sqrt{7} + (\sqrt{7})^2 \left[\because(a+b)^2=a^2+2 a b+b^2\right]$
= 3 + 2$\sqrt{21}$ + 7
$=10+2\sqrt{21}$
($\sqrt{3} + \sqrt{7})^2$
= ($\sqrt{3})^2 + 2 \times \sqrt{3} \times \sqrt{7} + (\sqrt{7})^2 \left[\because(a+b)^2=a^2+2 a b+b^2\right]$
= 3 + 2$\sqrt{21}$ + 7
$=10+2\sqrt{21}$
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