Question
Simplify the following:$2 \log 5+\log 8-\frac{1}{2} \log 4$
✓
Answer
$2 \log 5+\log 8-\frac{1}{2} \log 4$
$ =2 \log 5+\log 2^3-\frac{1}{2} \log 2^2$
$ =2 \log 5+3 \log 2-\frac{1}{2} \times 2 \log 2$
$ =2 \log 5+3 \log 2-\log 2$
$ =2 \log 5+2 \log 2 $
$ =2(\log 5+\log 2) $
$=2 \log (5 \times 2)$
$ =2 \log 10 $
$ =2 \times 1 $
$ =2 .$
$ =2 \log 5+\log 2^3-\frac{1}{2} \log 2^2$
$ =2 \log 5+3 \log 2-\frac{1}{2} \times 2 \log 2$
$ =2 \log 5+3 \log 2-\log 2$
$ =2 \log 5+2 \log 2 $
$ =2(\log 5+\log 2) $
$=2 \log (5 \times 2)$
$ =2 \log 10 $
$ =2 \times 1 $
$ =2 .$
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