Question
Simplify the following:$\frac{(\text{a}^{3\text{n-9}})^6}{\text{a}^{2\text{n}-4}}$
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Answer
$\frac{(\text{a}^{3\text{n-9}})^6}{\text{a}^{2\text{n}-4}}$$=\frac{\text{a}^{18\text{n}-54}}{\text{a}^{2\text{n-4}}}=\text{a}^{18\text{n}-2\text{n}-54 +4}$
$=\text{a}^{18\text{n}-2\text{n}-54+4}=\text{a}^{16\text{n}-50}$
$=\text{a}^{18\text{n}-2\text{n}-54+4}=\text{a}^{16\text{n}-50}$
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