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Number Systems — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsNumber Systems3 Marks
Question
Simplify the following:
$(\sqrt{3}-\sqrt{2})^2$
✓

Answer

$(\sqrt{3}-\sqrt{2})^2$
$=(\sqrt{3})^2+(\sqrt{2})^2-2(\sqrt{3})(\sqrt{2})$
$=3+2-2\sqrt{3\times2}=5-2\sqrt{6}$
$=(3+6+\frac{7}{3})\sqrt{3}$
$=\frac{34}{3}\sqrt{3}$

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