Question
Simplify the following:
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
✓
Answer
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
$=x \times x+x \times 4+3 x \times 2 x^2-3 x+4 x^2+4$
$=x^{(1+1)}+4 x+6 \times x^{(1+2)}-3 x+4 x^2+4$
$=x^2+4 x+6 x^3-3 x+4 x^2+4$
$=6 x^3+5 x^2+x+4$
$=x \times x+x \times 4+3 x \times 2 x^2-3 x+4 x^2+4$
$=x^{(1+1)}+4 x+6 \times x^{(1+2)}-3 x+4 x^2+4$
$=x^2+4 x+6 x^3-3 x+4 x^2+4$
$=6 x^3+5 x^2+x+4$
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