Question
The difference between two numbers is 7. Six times the smaller plus the larger is 77. Find the numbers.
✓
Answer
Let the smaller number be ‘x’.So, the larger number = x + 7.
According to question:
6x + (x + 7) = 77
6x + x + 7 = 77
7x + 7 = 77
Subtracting 7 from both sides, we get
7x + 7 - 7 = 77 - 7
7x = 70
Dividing both sides by 7, we get
$\frac{7\text{x}}{7}=\frac{70}{7}$
$\text{x}=10$
Thus, the smaller number = x = 10, and the larger number = x + 7 = 10 + 7 = 17.
The two required numbers are 10 and 17.
According to question:
6x + (x + 7) = 77
6x + x + 7 = 77
7x + 7 = 77
Subtracting 7 from both sides, we get
7x + 7 - 7 = 77 - 7
7x = 70
Dividing both sides by 7, we get
$\frac{7\text{x}}{7}=\frac{70}{7}$
$\text{x}=10$
Thus, the smaller number = x = 10, and the larger number = x + 7 = 10 + 7 = 17.
The two required numbers are 10 and 17.
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