Question
Simplify $\frac{x+2}{4 y} \div \frac{x^2-x-6}{12 y^2}$
✓
Answer
$\begin{aligned} & x ^2- x -6=( x -3)( x +2) \\ & \frac{x+2}{4 y } \div \frac{x^2-x-6}{12 y^2}=\frac{x+2}{4 y} \div \frac{(x-3)(x+2)}{12 y^2} \\ & =\frac{(x+2)}{4 y} \times \frac{12 y^2}{(x-3)(x+2)} \\ & =\frac{3 y}{x-3}\end{aligned}$
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