Question
Simplify:
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
✓
Answer
To simplify, we will use distributive law as follows:
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
$=x^2+4 x+6 x^3-3 x+4 x^2+4$
$=x^2+4 x^2+4 x-3 x+6 x^3+4$
$=5 x^2+x+6 x^3+4$
$x(x+4)+3 x\left(2 x^2-1\right)+4 x^2+4$
$=x^2+4 x+6 x^3-3 x+4 x^2+4$
$=x^2+4 x^2+4 x-3 x+6 x^3+4$
$=5 x^2+x+6 x^3+4$
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