Question
Simplify:
$1 \frac{3}{4}+2 \frac{5}{7}-1 \frac{3}{14}$
$1 \frac{3}{4}+2 \frac{5}{7}-1 \frac{3}{14}$
✓
Answer
$1 \frac{3}{4}+2 \frac{5}{7}-1 \frac{3}{14}=\frac{7}{4}+\frac{19}{7}-\frac{17}{14} $
$=\frac{7 \times 7}{4 \times 7}+\frac{19 \times 4}{7 \times 4}-\frac{17 \times 2}{14 \times 2} $
$=\frac{49}{28}+\frac{76}{28}-\frac{34}{28}=\frac{49+76-34}{28}=\frac{91}{28} $
$=3 \frac{7}{28}=3 \frac{1}{4}$
$=\frac{7 \times 7}{4 \times 7}+\frac{19 \times 4}{7 \times 4}-\frac{17 \times 2}{14 \times 2} $
$=\frac{49}{28}+\frac{76}{28}-\frac{34}{28}=\frac{49+76-34}{28}=\frac{91}{28} $
$=3 \frac{7}{28}=3 \frac{1}{4}$
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