Question
Simplify
(I) $\frac{3}{7} \times \frac{28}{15}÷\frac{14}{5}$
(ii) $\frac{3}{7}+\left(\frac{-2}{21}\right) \times\left(\frac{-5}{6}\right)$

Answer

(i) We have, $ \begin{aligned} \frac{3}{7} \times \frac{28}{15} ÷\frac{14}{5} =\frac{3}{7} \times \frac{28}{15} \times \frac{5}{14} =\frac{3}{7} \times\left(\frac{28}{15} \times \frac{5}{14}\right)=\frac{3}{7} \times \frac{2}{3}=\frac{2}{7} \end{aligned} $
(ii) We have, $\frac{3}{7}+\left(\frac{-2}{21}\right) \times\left(\frac{-5}{6}\right)=\frac{3}{7}+\left[\left(\frac{-2}{21}\right) \times\left(\frac{-5}{6}\right)\right]$
$=\frac{3}{7}+\left(\frac{-5}{-63}\right)=\frac{3}{7}+\frac{5}{63}=\frac{27+5}{63}=\frac{32}{63}$

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