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STD 12 - 2. inverse trigonometric function — Mathematics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceMathematicsSTD 12 - 2. inverse trigonometric function1 Mark
MCQ
${\sin ^{ - 1}}\frac{4}{5} + 2{\tan ^{ - 1}}\frac{1}{3} = $
  • ✓
    $\frac{\pi }{2}$
  • B
    $\frac{\pi }{3}$
  • C
    $\frac{\pi }{4}$
  • D
    None of these
✓

Answer

Correct option: A.
$\frac{\pi }{2}$
a
(a) ${\sin ^{ - 1}}\frac{4}{5} = {\tan ^{ - 1}}\frac{4}{3},{\rm{ }}2{\tan ^{ - 1}}\frac{1}{3} = {\tan ^{ - 1}}\frac{3}{4} = {\cot ^{ - 1}}\frac{4}{3}$ and ${\tan ^{ - 1}}x + {\cot ^{ - 1}}x = \frac{\pi }{2}$.

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