( ^ -1 x )= - Vidyadip

MCQ

$\sin \left(\cot ^{-1} x\right)=$

A
$\sqrt{1+x^2}$
B
x
C
$\left(1+x^2\right)^{-3 / 2}$
✓
$\frac{1}{\sqrt{1+x^2}}$

✓

Answer

Correct option: D.

$\frac{1}{\sqrt{1+x^2}}$

D

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "MCQ [1M]" from प्रतिलोम त्रिकोणमितीय फलन→प्रतिलोम त्रिकोणमितीय फलन — all question types→गणित कक्षा 12 साइन्स question papers→Bihar Board कक्षा 12 साइन्स question papers→Bihar Board question paper generator→

Similar questions

यदि $f(x)=\left|\begin{array}{ccc}0 & x-a & x-b \\ x+a & 0 & x-c \\ x+b & x+c & 0\end{array}\right|$, तब

$\left|\begin{array}{lll}21 & 11 & 10 \\ 25 & 15 & 10 \\ 64 & 27 & 37\end{array}\right|=$

$\int e^x\left(x^3+3 x^2\right) d x=$

$\int \frac{x e^x}{(x+1)^2} d x=$

$\int \tan 10 x d x=$

यदि $A=\left[\begin{array}{ll}2 & 3 \\ 1 & 4\end{array}\right]$, तब $\operatorname{adj} A=$

$\frac{d y}{d x}=1+x+y+x y$ का हल है :

यदि $\left[\begin{array}{cc}x+y & y \\ 2 x & x-y\end{array}\right]\left[\begin{array}{c}2 \\ -1\end{array}\right]=\left[\begin{array}{l}3 \\ 2\end{array}\right]$, तो $x \cdot y=$

$\left[\begin{array}{lll}\vec{I} & \vec{J} & \vec{K}\end{array}\right]$ का मानांकन है :

सदिशों $2 \hat{i}+3 \hat{j}+\hat{k}$ एवं $2 \hat{i}-\hat{j}-\hat{k}$ के बीच का कोण होगा :