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प्रतिलोम त्रिकोणमितीय फलन गणित - प्रतिलोम त्रिकोणमितीय फलन

Bihar Board (BSEB) - कक्षा 12 साइन्स - गणित (BSEB - Hindi Medium). 284 questions in this chapter.

Question types

प्रतिलोम त्रिकोणमितीय फलन question types

284 questions across 3 question groups — pick any mix to generate a गणित paper with step-by-step answer keys.

284
Questions
3
Question groups
5
Question types
Sample Questions

प्रतिलोम त्रिकोणमितीय फलन questions

One sample from each question group in this chapter. Select any group above to see the full set with answer keys.

Q 1MCQ [1M]1 Mark
समीकरण $\sqrt{1+\cos 2 x}=\sqrt{2} \cos ^{-1}(\cos x)$ in $\left[\frac{\pi}{2}, \pi\right]$ के  वास्तविक हलों की संख्या है
  • ✓
    $0$
  • B
    1
  • C
    2
  • D
    अनंत

Answer: A.

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Q 2MCQ [1M]1 Mark
व्यंजक $\tan \left(\frac{1}{2} \cos ^{-1} \frac{2}{\sqrt{5}}\right)$ का मान है
  • A
    $2+\sqrt{5}$
  • ✓
    $\sqrt{5}-2$
  • C
    $\frac{\sqrt{5}+2}{2}$
  • D
    $5+\sqrt{2}$

Answer: B.

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Q 3MCQ [1M]1 Mark
व्यंजक $2 \sec ^{-1} 2+\sin ^{-1}\left(\frac{1}{2}\right)$ का मान है
  • A
    $\frac{\pi}{6}$
  • ✓
    $\frac{5 \pi}{6}$
  • C
    $\frac{7 \pi}{6}$
  • D
    1

Answer: B.

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Q 4MCQ [1M]1 Mark
यदि $|x| \leq 1$, तब $2 \tan ^{-1} x+\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$ बराबर है
  • ✓
    $4 \tan ^{-1} x$
  • B
    $0$
  • C
    $\frac{\pi}{2}$
  • D
    $\pi$

Answer: A.

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Q 5MCQ [1M]1 Mark
यदि $\tan ^{-1} x+\tan ^{-1} y=\frac{4 \pi}{5}$, तो $\cot ^{-1} x+$$\cot ^{-1} y$ बराबर है
  • ✓
    $\frac{\pi}{5}$
  • B
    $\frac{2 \pi}{5}$
  • C
    $\frac{3 \pi}{5}$
  • D
    $\pi$

Answer: A.

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