Question
Sin (tan–1 x), | x | < 1 is equal to

Answer

Let tan-1 x = y, then tan y = x $\Rightarrow$ sin y = $\frac{x}{\sqrt{1+x^{2}}}$
$\therefore$  y = sin-1 $\left(\frac{x}{\sqrt{1+x^{2}}}\right)$
$\Rightarrow$ $\tan ^{-1} x=\sin ^{-1}\left(\frac{x}{\sqrt{1+x^{2}}}\right)$
$\Rightarrow$ sin (tan-1 x) = sin$\left(\sin ^{-1}\left(\frac{x}{\sqrt{1+x^{2}}}\right)\right)$
= $\frac{x}{\sqrt{1+x^{2}}}$

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