MCQ
$\sin \theta=\frac{1}{2}$ then $\theta=?$
- A30°
- B45°
- C60°
- D90°
$\sin \theta=\frac{1}{2}$
$\therefore \theta=30^{\circ} \quad \ldots\left[\sin 30^{\circ}=\frac{1}{2}\right]$
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