electronegativity depends on $s$ - character, more is the $s$ - character, more is the electronegativity. So, the order for electronegativity should be $sp \,> \,sp ^2\,>\,sp ^3$

bond angle between same hybrid orbitals is in the following order

$sp \left(180^{\circ}\right)\,>\, sp ^2\left(120^{\circ}\right)\,>\,sp ^3\left(109.5^{\circ}\right)$

Size $\rightarrow$ more $s$-character $\rightarrow$ more compact $\rightarrow$ smaller size.

So, the given order is correct, $sp \,<\, sp ^2\,<\,sp ^3$.

Energy level $\rightarrow$ since $s$-orbitals have lower energy closer than $p$ - as they allow closer proximity of the $e^{-}$to the nuclear. Thus, more $p$ - character more energy.

So, the order will be $sp \,<\,sp ^2\,<\,sp ^3$