Question
समीकरण ${2^{x + 2}}{27^{x/(x - 1)}} = 9$ के मूल हैं
$(x + 2)\log 2 + \left( {\frac{{3x}}{{x - 1}}} \right)\log 3 = 2\log 3$
==> $(x + 2)\left( {\log 2 + \frac{1}{{x - 1}}\log 3} \right) = 0$
==> $x = - 2$ या $\frac{1}{{1 - x}} = \frac{{\log 2}}{{\log 3}}$
==>$1 - x = \frac{{\log 3}}{{\log 2}}$
$⇒x = 1 - \frac{{\log 3}}{{\log 2}}$
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