Rajasthan Boardहिन्दी माध्यमकक्षा 12 साइन्सगणितअवकल समीकरण1 Mark
Question
समीकरण $\frac{d y}{d x}+\cos x \cdot \tan y=0$ का हल है-
✓
Answer
(A) $\log \sin y+\sin x=c$ $\frac{d y}{d x}+\cos x \cdot \tan y=0$ $\Rightarrow \quad \frac{d y}{d x}=-\cos x \cdot \tan y$ $\Rightarrow \quad \frac{d y}{\tan y}=-\cos x d x$ या $\cot y d y=-\cos x d x$ इसलिए $\int \cot y d y=-\int \cos x d x$ $\log \sin y=-\sin x+c$ $\Rightarrow \quad \log \sin y+\sin x=c$ अतः सही विकल्प (A) है।
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.