સમીકરણોની સંહતિ $7 x+6 y-2 z=0$ ; $3 x+4 y+2 z=0$ ; ${x}-2{y}-6{z}=0,$ ને.. . . . .
JEE MAIN 2020, Difficult
Download our app for free and get started
$7 \mathrm{x}+6 \mathrm{y}-2 \mathrm{z}=0\dots(1)$
$3 x+4 y+2 z=0\dots(2)$
$\mathrm{x}-2 \mathrm{y}-6 \mathrm{z}=0\dots(3)$
$\Delta=\left|\begin{array}{ccc}{7} & {6} & {-2} \\ {3} & {4} & {2} \\ {1} & {-2} & {-6}\end{array}\right|=0 \Rightarrow$ infinite solutions
Now $(1)+(2) \Rightarrow y=-x$ put in $(1),(2)$ and $(3)$
all will lead to $x=2 z$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1જો $A = \left[ {\begin{array}{*{20}{c}}1&2&{ - 1}\\3&0&{\,\,2}\\4&5&{\,\,0}\end{array}} \right]$, $B = \left[ {\begin{array}{*{20}{c}}1&0&0\\2&1&0\\0&1&3\end{array}} \right],$ તો $AB = \ . ......$View Solution
- 2જો $A = \left[ {\begin{array}{*{20}{c}}3&{ - 5}\\{ - 4}&2\end{array}} \right],$ તો ${A^2} - 5A = $View Solution
- 3જો $A = \left[ {\begin{array}{*{20}{c}}2&2\\{ - 3}&2\end{array}} \right]$ અને $B = \left[ {\begin{array}{*{20}{c}}0&{ - 1}\\1&0\end{array}} \right],$ તો ${({B^{ - 1}}{A^{ - 1}})^{ - 1}}=$View Solution
- 4$A = \left[ {\begin{array}{*{20}{c}}4&6&{ - 1}\\3&0&2\\1&{ - 2}&5\end{array}} \right]$,$B = \left[ {\begin{array}{*{20}{c}}2&4\\0&1\\{ - 1}&2\end{array}} \right],\,\,C = \left[ {\begin{array}{*{20}{c}}3\\1\\2\end{array}} \right]$, તો ક્યૂ સમીકરણ વ્યખ્યાયિત નથી.View Solution
- 5જો $A = \left[ {\begin{array}{*{20}{c}} 3&7\\ 1&2 \end{array}} \right]$ તો $|A^{2011} -5A^{2010}|$ મેળવો.View Solution
- 6ધારો કે $S _1$ અને $S _2$ એવા દરેક $a \in R$ - \{0\}ના ગણો દર્શાવે છે જેના માટે સુરેખ સમીકરણ સંહતિView Solution
$a x+2 a y-3 a z=1$
$(2 a+1) x+(2 a+3) y+(a+1) z=2$
$(3 a+5) x+(a+5) y+(a+2) z=3$
ને અનુક્રમે અનન્ય ઉકેલ તથા અસંખ્ય ઉકેલો હોય. તો
- 7શ્રેણિક $\left( {\begin{array}{*{20}{c}}1&{ - 2}\\3&4\end{array}} \right)$ નો વ્યસ્ત મેળવો.View Solution
- 8જો $A=$ $\left[ {\begin{array}{*{20}{c}}{5a}&{ - b}\\3&2\end{array}} \right]$ અને $A\;adj\;A = A\;{A^T},$તો $5a+b= $. . . . .View Solution
- 9$\left| {\,\begin{array}{*{20}{c}}1&5&\pi \\{{{\log }_e}e}&5&{\sqrt 5 }\\{{{\log }_{10}}10}&5&e\end{array}\,} \right| = $View Solution
- 10જો $\lambda \in R$ માટે સુરેખ સમીકરણ સહિતાView Solution
$2 x_{1}-4 x_{2}+\lambda x_{3}=1$
$x_{1}-6 x_{2}+x_{3}=2$
$\lambda x_{1}-10 x_{2}+4 x_{3}=3$ નો ઉકેલ શક્ય નથી